Md-15 Keys and Couplings - Uni
2007-8-15 · Example Problem 15-1: Design of Keys (cont’d.)d.) – Find length required for compression, using lowest value of yield, which is key value S y = 51 ksi..226 51,000 .125 .5 4(180 ) 4 2 = − = = L lb in in in in lb L S t D T L c – With SF = 2.5: L = 2.5 (.226) L = .565 inch – This would be the minimum length. A longer key may be useful if the hub length is longer.
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